35250012197 has 4 divisors (see below), whose sum is σ = 35255704800. Its totient is φ = 35244319596.

The previous prime is 35250012179. The next prime is 35250012209. The reversal of 35250012197 is 79121005253.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 79121005253 = 619 ⋅127820687.

It is a cyclic number.

It is not a de Polignac number, because 35250012197 - 2¹⁶ = 35249946661 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (35250012137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2837003 + ... + 2849400.

It is an arithmetic number, because the mean of its divisors is an integer number (8813926200).

Almost surely, 2^35250012197 is an apocalyptic number.

It is an amenable number.

35250012197 is a deficient number, since it is larger than the sum of its proper divisors (5692603).

35250012197 is an equidigital number, since it uses as much as digits as its factorization.

35250012197 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5692602.

The product of its (nonzero) digits is 18900, while the sum is 35.

The spelling of 35250012197 in words is "thirty-five billion, two hundred fifty million, twelve thousand, one hundred ninety-seven".