Base | Representation |
---|---|
bin | 1010010000100110101… |
… | …10111111110110110111 |
3 | 1020200220011201211002001 |
4 | 11020103112333312313 |
5 | 21233421100122403 |
6 | 425535234000131 |
7 | 34316402350042 |
oct | 5102326776667 |
9 | 1220804654061 |
10 | 352512114103 |
11 | 126554997906 |
12 | 5839b716047 |
13 | 2731b17c986 |
14 | 130c1357c59 |
15 | 9282873c1d |
hex | 52135bfdb7 |
352512114103 has 4 divisors (see below), whose sum is σ = 355631690448. Its totient is φ = 349392537760.
The previous prime is 352512114083. The next prime is 352512114107. The reversal of 352512114103 is 301411215253.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301411215253 = 55721 ⋅5409293.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-352512114103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (352512114107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1559788003 + ... + 1559788228.
It is an arithmetic number, because the mean of its divisors is an integer number (88907922612).
Almost surely, 2352512114103 is an apocalyptic number.
352512114103 is a deficient number, since it is larger than the sum of its proper divisors (3119576345).
352512114103 is a wasteful number, since it uses less digits than its factorization.
352512114103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3119576344.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 352512114103 its reverse (301411215253), we get a palindrome (653923329356).
The spelling of 352512114103 in words is "three hundred fifty-two billion, five hundred twelve million, one hundred fourteen thousand, one hundred three".
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