Base | Representation |
---|---|
bin | 100000110101001001… |
… | …011110010001111101 |
3 | 10100222201202101022011 |
4 | 200311021132101331 |
5 | 1034143330223031 |
6 | 24105544051221 |
7 | 2355364035106 |
oct | 406511362175 |
9 | 110881671264 |
10 | 35251414141 |
11 | 13a4a560219 |
12 | 69b9763b11 |
13 | 342a33cc48 |
14 | 19c5a733ad |
15 | db4b936b1 |
hex | 83525e47d |
35251414141 has 2 divisors, whose sum is σ = 35251414142. Its totient is φ = 35251414140.
The previous prime is 35251414109. The next prime is 35251414157. The reversal of 35251414141 is 14141415253.
35251414141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30712562500 + 4538851641 = 175250^2 + 67371^2 .
It is a cyclic number.
It is not a de Polignac number, because 35251414141 - 25 = 35251414109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35251414181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17625707070 + 17625707071.
It is an arithmetic number, because the mean of its divisors is an integer number (17625707071).
Almost surely, 235251414141 is an apocalyptic number.
It is an amenable number.
35251414141 is a deficient number, since it is larger than the sum of its proper divisors (1).
35251414141 is an equidigital number, since it uses as much as digits as its factorization.
35251414141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9600, while the sum is 31.
Adding to 35251414141 its reverse (14141415253), we get a palindrome (49392829394).
The spelling of 35251414141 in words is "thirty-five billion, two hundred fifty-one million, four hundred fourteen thousand, one hundred forty-one".
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