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35255414132501 is a prime number
BaseRepresentation
bin10000000010000100010100…
…11011111000111100010101
311121211101101102120011120112
420001002022123320330111
514110111042004220001
6202552040315012405
710266056012431103
oct1001021233707425
9147741342504515
1035255414132501
1110262812197732
123b5489aa3a105
1316897571700a4
1489c52a608c73
1541211a7c1cbb
hex20108a6f8f15

35255414132501 has 2 divisors, whose sum is σ = 35255414132502. Its totient is φ = 35255414132500.

The previous prime is 35255414132489. The next prime is 35255414132507. The reversal of 35255414132501 is 10523141455253.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34973799238225 + 281614894276 = 5913865^2 + 530674^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-35255414132501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35255414132507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17627707066250 + 17627707066251.

It is an arithmetic number, because the mean of its divisors is an integer number (17627707066251).

Almost surely, 235255414132501 is an apocalyptic number.

It is an amenable number.

35255414132501 is a deficient number, since it is larger than the sum of its proper divisors (1).

35255414132501 is an equidigital number, since it uses as much as digits as its factorization.

35255414132501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360000, while the sum is 41.

Adding to 35255414132501 its reverse (10523141455253), we get a palindrome (45778555587754).

The spelling of 35255414132501 in words is "thirty-five trillion, two hundred fifty-five billion, four hundred fourteen million, one hundred thirty-two thousand, five hundred one".