Base | Representation |
---|---|
bin | 1010010001100001000… |
… | …01100100100011011001 |
3 | 1020202011021110101121001 |
4 | 11020300201210203121 |
5 | 21240421331100423 |
6 | 430055553345001 |
7 | 34334463414541 |
oct | 5106041444331 |
9 | 1222137411531 |
10 | 353001425113 |
11 | 126786113477 |
12 | 584b7568161 |
13 | 2739866170c |
14 | 1312a32a321 |
15 | 92b07c9cad |
hex | 52308648d9 |
353001425113 has 2 divisors, whose sum is σ = 353001425114. Its totient is φ = 353001425112.
The previous prime is 353001425099. The next prime is 353001425123. The reversal of 353001425113 is 311524100353.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 274044921049 + 78956504064 = 523493^2 + 280992^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-353001425113 is a prime.
It is a super-2 number, since 2×3530014251132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (353001425123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 176500712556 + 176500712557.
It is an arithmetic number, because the mean of its divisors is an integer number (176500712557).
Almost surely, 2353001425113 is an apocalyptic number.
It is an amenable number.
353001425113 is a deficient number, since it is larger than the sum of its proper divisors (1).
353001425113 is an equidigital number, since it uses as much as digits as its factorization.
353001425113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 353001425113 its reverse (311524100353), we get a palindrome (664525525466).
The spelling of 353001425113 in words is "three hundred fifty-three billion, one million, four hundred twenty-five thousand, one hundred thirteen".
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