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35312140775749 is a prime number
BaseRepresentation
bin10000000011101101111111…
…00110110111000101000101
311122000210210210202020000111
420001312333212313011011
514112023231014310444
6203034101251513021
710303134524101465
oct1001667746670505
9148023723666014
1035312140775749
1110284881978382
123b638905b8771
131691bc76b6096
148a118c459ba5
1541383a986234
hex201dbf9b7145

35312140775749 has 2 divisors, whose sum is σ = 35312140775750. Its totient is φ = 35312140775748.

The previous prime is 35312140775729. The next prime is 35312140775771. The reversal of 35312140775749 is 94757704121353.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21962485552225 + 13349655223524 = 4686415^2 + 3653718^2 .

It is a cyclic number.

It is not a de Polignac number, because 35312140775749 - 27 = 35312140775621 is a prime.

It is a super-2 number, since 2×353121407757492 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 35312140775693 and 35312140775702.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35312140775729) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17656070387874 + 17656070387875.

It is an arithmetic number, because the mean of its divisors is an integer number (17656070387875).

Almost surely, 235312140775749 is an apocalyptic number.

It is an amenable number.

35312140775749 is a deficient number, since it is larger than the sum of its proper divisors (1).

35312140775749 is an equidigital number, since it uses as much as digits as its factorization.

35312140775749 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22226400, while the sum is 58.

The spelling of 35312140775749 in words is "thirty-five trillion, three hundred twelve billion, one hundred forty million, seven hundred seventy-five thousand, seven hundred forty-nine".