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35314213537 is a prime number
BaseRepresentation
bin100000111000111001…
…000010001010100001
310101011002220220212201
4200320321002022201
51034310414313122
624120110053201
72360055601531
oct407071021241
9111132826781
1035314213537
1113a81a53349
126a167aa201
13343a35a155
1419d013d4c1
15dba44aa27
hex838e422a1

35314213537 has 2 divisors, whose sum is σ = 35314213538. Its totient is φ = 35314213536.

The previous prime is 35314213453. The next prime is 35314213541. The reversal of 35314213537 is 73531241353.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29361165201 + 5953048336 = 171351^2 + 77156^2 .

It is a cyclic number.

It is not a de Polignac number, because 35314213537 - 211 = 35314211489 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 35314213496 and 35314213505.

It is not a weakly prime, because it can be changed into another prime (35314213037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17657106768 + 17657106769.

It is an arithmetic number, because the mean of its divisors is an integer number (17657106769).

Almost surely, 235314213537 is an apocalyptic number.

It is an amenable number.

35314213537 is a deficient number, since it is larger than the sum of its proper divisors (1).

35314213537 is an equidigital number, since it uses as much as digits as its factorization.

35314213537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 113400, while the sum is 37.

The spelling of 35314213537 in words is "thirty-five billion, three hundred fourteen million, two hundred thirteen thousand, five hundred thirty-seven".