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35344143142117 is a prime number
BaseRepresentation
bin10000000100101001100110…
…00110001100110011100101
311122010212102002211212122221
420002110303012030303211
514113034301121021432
6203100513013352341
710305346546526245
oct1002246306146345
9148125362755587
1035344143142117
1110297404424947
123b69b220386b1
131694c27873644
148a29467b7b25
154145b028db97
hex20253318cce5

35344143142117 has 2 divisors, whose sum is σ = 35344143142118. Its totient is φ = 35344143142116.

The previous prime is 35344143142111. The next prime is 35344143142151. The reversal of 35344143142117 is 71124134144353.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35134556808481 + 209586333636 = 5927441^2 + 457806^2 .

It is an emirp because it is prime and its reverse (71124134144353) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35344143142117 - 219 = 35344142617829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35344143142111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17672071571058 + 17672071571059.

It is an arithmetic number, because the mean of its divisors is an integer number (17672071571059).

Almost surely, 235344143142117 is an apocalyptic number.

It is an amenable number.

35344143142117 is a deficient number, since it is larger than the sum of its proper divisors (1).

35344143142117 is an equidigital number, since it uses as much as digits as its factorization.

35344143142117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 483840, while the sum is 43.

The spelling of 35344143142117 in words is "thirty-five trillion, three hundred forty-four billion, one hundred forty-three million, one hundred forty-two thousand, one hundred seventeen".