Base | Representation |
---|---|
bin | 100000111101111010… |
… | …100110110110001101 |
3 | 10101100222112201122111 |
4 | 200331322212312031 |
5 | 1034444004341023 |
6 | 24132320544021 |
7 | 2362131246634 |
oct | 407572466615 |
9 | 111328481574 |
10 | 35398512013 |
11 | 140155a0007 |
12 | 6a3aa82011 |
13 | 3451963bc7 |
14 | 19db40451b |
15 | dc2a4d00d |
hex | 83dea6d8d |
35398512013 has 2 divisors, whose sum is σ = 35398512014. Its totient is φ = 35398512012.
The previous prime is 35398511977. The next prime is 35398512109. The reversal of 35398512013 is 31021589353.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34090821769 + 1307690244 = 184637^2 + 36162^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35398512013 is a prime.
It is a super-3 number, since 3×353985120133 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35398512713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17699256006 + 17699256007.
It is an arithmetic number, because the mean of its divisors is an integer number (17699256007).
Almost surely, 235398512013 is an apocalyptic number.
It is an amenable number.
35398512013 is a deficient number, since it is larger than the sum of its proper divisors (1).
35398512013 is an equidigital number, since it uses as much as digits as its factorization.
35398512013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 35398512013 in words is "thirty-five billion, three hundred ninety-eight million, five hundred twelve thousand, thirteen".
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