Base | Representation |
---|---|
bin | 1010010011011001011… |
… | …10100001011001111011 |
3 | 1020211202200000010110012 |
4 | 11021230232201121323 |
5 | 21300003412444201 |
6 | 430344114012135 |
7 | 34401506462444 |
oct | 5115456413173 |
9 | 1224680003405 |
10 | 354011453051 |
11 | 127154266403 |
12 | 5873987704b |
13 | 274c99a0099 |
14 | 131c45282cb |
15 | 931e2dc5bb |
hex | 526cba167b |
354011453051 has 2 divisors, whose sum is σ = 354011453052. Its totient is φ = 354011453050.
The previous prime is 354011453017. The next prime is 354011453053. The reversal of 354011453051 is 150354110453.
It is a strong prime.
It is an emirp because it is prime and its reverse (150354110453) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 354011453051 - 26 = 354011452987 is a prime.
Together with 354011453053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 354011452999 and 354011453017.
It is not a weakly prime, because it can be changed into another prime (354011453053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177005726525 + 177005726526.
It is an arithmetic number, because the mean of its divisors is an integer number (177005726526).
Almost surely, 2354011453051 is an apocalyptic number.
354011453051 is a deficient number, since it is larger than the sum of its proper divisors (1).
354011453051 is an equidigital number, since it uses as much as digits as its factorization.
354011453051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 354011453051 in words is "three hundred fifty-four billion, eleven million, four hundred fifty-three thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •