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3540313 = 7505759
BaseRepresentation
bin1101100000010101011001
320122212101201
431200111121
51401242223
6203514201
742043420
oct15402531
96585351
103540313
111aa8987
121228961
1396c57a
146822b7
1549dead
hex360559

3540313 has 4 divisors (see below), whose sum is σ = 4046080. Its totient is φ = 3034548.

The previous prime is 3540311. The next prime is 3540323. The reversal of 3540313 is 3130453.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3540313 - 21 = 3540311 is a prime.

It is a super-2 number, since 2×35403132 = 25067632275938, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3540311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252873 + ... + 252886.

It is an arithmetic number, because the mean of its divisors is an integer number (1011520).

Almost surely, 23540313 is an apocalyptic number.

It is an amenable number.

3540313 is a deficient number, since it is larger than the sum of its proper divisors (505767).

3540313 is an equidigital number, since it uses as much as digits as its factorization.

3540313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 505766.

The product of its (nonzero) digits is 540, while the sum is 19.

The square root of 3540313 is about 1881.5719491957. The cubic root of 3540313 is about 152.4101486297.

Adding to 3540313 its reverse (3130453), we get a palindrome (6670766).

The spelling of 3540313 in words is "three million, five hundred forty thousand, three hundred thirteen".

Divisors: 1 7 505759 3540313