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354131121131197 is a prime number
BaseRepresentation
bin101000010000101001001001…
…1101011011100111010111101
31201102212121022201100011102121
41100201102103223130322331
5332404041014002144242
63253101331404322541
7134410062211354624
oct12041222353347275
91642777281304377
10354131121131197
11a292318a776813
1233874b97b43451
131227a562b66c87
1463640756c86bb
152ae1b6a949667
hex1421493adcebd

354131121131197 has 2 divisors, whose sum is σ = 354131121131198. Its totient is φ = 354131121131196.

The previous prime is 354131121131173. The next prime is 354131121131213. The reversal of 354131121131197 is 791131121131453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 350883553116996 + 3247568014201 = 18731886^2 + 1802101^2 .

It is an emirp because it is prime and its reverse (791131121131453) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-354131121131197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (354131121171197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177065560565598 + 177065560565599.

It is an arithmetic number, because the mean of its divisors is an integer number (177065560565599).

Almost surely, 2354131121131197 is an apocalyptic number.

It is an amenable number.

354131121131197 is a deficient number, since it is larger than the sum of its proper divisors (1).

354131121131197 is an equidigital number, since it uses as much as digits as its factorization.

354131121131197 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 68040, while the sum is 43.

The spelling of 354131121131197 in words is "three hundred fifty-four trillion, one hundred thirty-one billion, one hundred twenty-one million, one hundred thirty-one thousand, one hundred ninety-seven".