Base | Representation |
---|---|
bin | 110011100010101111101… |
… | …001110110001001101111 |
3 | 110112121112001221210121211 |
4 | 303202233221312021233 |
5 | 431013004002100130 |
6 | 11311101121135251 |
7 | 513621030351403 |
oct | 63425751661157 |
9 | 13477461853554 |
10 | 3542000034415 |
11 | 1146176752717 |
12 | 49256878a527 |
13 | 1c90171ba13b |
14 | c3610191103 |
15 | 6220772ba2a |
hex | 338afa7626f |
3542000034415 has 16 divisors (see below), whose sum is σ = 4268141324928. Its totient is φ = 2821796973216.
The previous prime is 3542000034359. The next prime is 3542000034421. The reversal of 3542000034415 is 5144300002453.
It is a cyclic number.
It is not a de Polignac number, because 3542000034415 - 211 = 3542000032367 is a prime.
It is a super-3 number, since 3×35420000344153 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 370329 + ... + 2687218.
It is an arithmetic number, because the mean of its divisors is an integer number (266758832808).
Almost surely, 23542000034415 is an apocalyptic number.
3542000034415 is a deficient number, since it is larger than the sum of its proper divisors (726141290513).
3542000034415 is a wasteful number, since it uses less digits than its factorization.
3542000034415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3058518.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 3542000034415 its reverse (5144300002453), we get a palindrome (8686300036868).
The spelling of 3542000034415 in words is "three trillion, five hundred forty-two billion, thirty-four thousand, four hundred fifteen".
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