3542042533 has 4 divisors (see below), whose sum is σ = 3591930528. Its totient is φ = 3492154540.

The previous prime is 3542042503. The next prime is 3542042561. The reversal of 3542042533 is 3352402453.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3352402453 = 83 ⋅40390391.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3542042533 is a prime.

It is a super-3 number, since 3×3542042533³ (a number of 30 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3542042495 and 3542042504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3542042503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24943891 + ... + 24944032.

It is an arithmetic number, because the mean of its divisors is an integer number (897982632).

Almost surely, 2^3542042533 is an apocalyptic number.

It is an amenable number.

3542042533 is a deficient number, since it is larger than the sum of its proper divisors (49887995).

3542042533 is an equidigital number, since it uses as much as digits as its factorization.

3542042533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49887994.

The product of its (nonzero) digits is 43200, while the sum is 31.

The square root of 3542042533 is about 59515.0613962550. The cubic root of 3542042533 is about 1524.3496333468.

Adding to 3542042533 its reverse (3352402453), we get a palindrome (6894444986).

The spelling of 3542042533 in words is "three billion, five hundred forty-two million, forty-two thousand, five hundred thirty-three".