Base | Representation |
---|---|
bin | 1010010011110000100… |
… | …10110000001110011001 |
3 | 1020212021012010202020211 |
4 | 11021320102300032121 |
5 | 21300403102002223 |
6 | 430415245051121 |
7 | 34406354035060 |
oct | 5117022601631 |
9 | 1225235122224 |
10 | 354205500313 |
11 | 127243852a45 |
12 | 58792856aa1 |
13 | 2752ac51a52 |
14 | 132021db1d7 |
15 | 933136cd0d |
hex | 52784b0399 |
354205500313 has 4 divisors (see below), whose sum is σ = 404806286080. Its totient is φ = 303604714548.
The previous prime is 354205500241. The next prime is 354205500329. The reversal of 354205500313 is 313005502453.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 354205500313 - 217 = 354205369241 is a prime.
It is a super-3 number, since 3×3542055003133 (a number of 36 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (354205510313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25300392873 + ... + 25300392886.
It is an arithmetic number, because the mean of its divisors is an integer number (101201571520).
Almost surely, 2354205500313 is an apocalyptic number.
It is an amenable number.
354205500313 is a deficient number, since it is larger than the sum of its proper divisors (50600785767).
354205500313 is an equidigital number, since it uses as much as digits as its factorization.
354205500313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50600785766.
The product of its (nonzero) digits is 27000, while the sum is 31.
The spelling of 354205500313 in words is "three hundred fifty-four billion, two hundred five million, five hundred thousand, three hundred thirteen".
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