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35421402544421 is a prime number
BaseRepresentation
bin10000000110111001100000…
…00111011011100100100101
311122102020211110001011101112
420003130300013123210211
514120321013022410141
6203200211230434405
710314053242600145
oct1003346007334445
9148366743034345
1035421402544421
1110317150336353
123b80aa4062a05
13169c2bac790ca
148a6595592925
154165d2d587eb
hex2037301db925

35421402544421 has 2 divisors, whose sum is σ = 35421402544422. Its totient is φ = 35421402544420.

The previous prime is 35421402544369. The next prime is 35421402544519. The reversal of 35421402544421 is 12444520412453.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33604756835521 + 1816645708900 = 5796961^2 + 1347830^2 .

It is a cyclic number.

It is not a de Polignac number, because 35421402544421 - 226 = 35421335435557 is a prime.

It is a super-3 number, since 3×354214025444213 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35421402564421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17710701272210 + 17710701272211.

It is an arithmetic number, because the mean of its divisors is an integer number (17710701272211).

Almost surely, 235421402544421 is an apocalyptic number.

It is an amenable number.

35421402544421 is a deficient number, since it is larger than the sum of its proper divisors (1).

35421402544421 is an equidigital number, since it uses as much as digits as its factorization.

35421402544421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 614400, while the sum is 41.

Adding to 35421402544421 its reverse (12444520412453), we get a palindrome (47865922956874).

The spelling of 35421402544421 in words is "thirty-five trillion, four hundred twenty-one billion, four hundred two million, five hundred forty-four thousand, four hundred twenty-one".