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354214315021 = 750602045003
BaseRepresentation
bin1010010011110001101…
…00011000010000001101
31020212021210201120202111
411021320310120100031
521300412331040041
6430420202024021
734406521666660
oct5117064302015
91225253646674
10354214315021
11127248823626
12587957a8011
132752ca19c58
14132034536d7
15933200e981
hex5278d1840d

354214315021 has 4 divisors (see below), whose sum is σ = 404816360032. Its totient is φ = 303612270012.

The previous prime is 354214314997. The next prime is 354214315033. The reversal of 354214315021 is 120513412453.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 354214315021 - 217 = 354214183949 is a prime.

It is a super-3 number, since 3×3542143150213 (a number of 36 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (354214316021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25301022495 + ... + 25301022508.

It is an arithmetic number, because the mean of its divisors is an integer number (101204090008).

Almost surely, 2354214315021 is an apocalyptic number.

It is an amenable number.

354214315021 is a deficient number, since it is larger than the sum of its proper divisors (50602045011).

354214315021 is an equidigital number, since it uses as much as digits as its factorization.

354214315021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50602045010.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 354214315021 its reverse (120513412453), we get a palindrome (474727727474).

The spelling of 354214315021 in words is "three hundred fifty-four billion, two hundred fourteen million, three hundred fifteen thousand, twenty-one".

Divisors: 1 7 50602045003 354214315021