Base | Representation |
---|---|
bin | 1101001100100001… |
… | …0100000101100001 |
3 | 100010212012222111121 |
4 | 3103020110011201 |
5 | 24223244001001 |
6 | 1343253012241 |
7 | 153530652034 |
oct | 32310240541 |
9 | 10125188447 |
10 | 3542172001 |
11 | 1558511285 |
12 | 82a324081 |
13 | 445b13984 |
14 | 25861901b |
15 | 15ae8c6a1 |
hex | d3214161 |
3542172001 has 2 divisors, whose sum is σ = 3542172002. Its totient is φ = 3542172000.
The previous prime is 3542171981. The next prime is 3542172041. The reversal of 3542172001 is 1002712453.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3038214400 + 503957601 = 55120^2 + 22449^2 .
It is a cyclic number.
It is not a de Polignac number, because 3542172001 - 231 = 1394688353 is a prime.
It is a super-3 number, since 3×35421720013 (a number of 30 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (3542172041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1771086000 + 1771086001.
It is an arithmetic number, because the mean of its divisors is an integer number (1771086001).
Almost surely, 23542172001 is an apocalyptic number.
It is an amenable number.
3542172001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3542172001 is an equidigital number, since it uses as much as digits as its factorization.
3542172001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1680, while the sum is 25.
The square root of 3542172001 is about 59516.1490773723. The cubic root of 3542172001 is about 1524.3682056905.
Adding to 3542172001 its reverse (1002712453), we get a palindrome (4544884454).
It can be divided in two parts, 35 and 42172001, that added together give a square (42172036 = 64942).
The spelling of 3542172001 in words is "three billion, five hundred forty-two million, one hundred seventy-two thousand, one".
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