35422044041 has 2 divisors, whose sum is σ = 35422044042. Its totient is φ = 35422044040.

The previous prime is 35422044037. The next prime is 35422044043. The reversal of 35422044041 is 14044022453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34001884816 + 1420159225 = 184396^2 + 37685^2 .

It is a cyclic number.

It is not a de Polignac number, because 35422044041 - 2² = 35422044037 is a prime.

It is a super-3 number, since 3×35422044041³ (a number of 33 digits) contains 333 as substring.

Together with 35422044043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 35422043995 and 35422044013.

It is not a weakly prime, because it can be changed into another prime (35422044043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17711022020 + 17711022021.

It is an arithmetic number, because the mean of its divisors is an integer number (17711022021).

Almost surely, 2^35422044041 is an apocalyptic number.

It is an amenable number.

35422044041 is a deficient number, since it is larger than the sum of its proper divisors (1).

35422044041 is an equidigital number, since it uses as much as digits as its factorization.

35422044041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15360, while the sum is 29.

Adding to 35422044041 its reverse (14044022453), we get a palindrome (49466066494).

The spelling of 35422044041 in words is "thirty-five billion, four hundred twenty-two million, forty-four thousand, forty-one".