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3542405330407 is a prime number
BaseRepresentation
bin110011100011000111110…
…011111011010111100111
3110112122120022120222012111
4303203013303323113213
5431014321231033112
611311205240101451
7513634051331356
oct63430763732747
913478508528174
103542405330407
111146364505589
12492660464887
131c9080164158
14c364bd3399d
156222d0d95a7
hex338c7cfb5e7

3542405330407 has 2 divisors, whose sum is σ = 3542405330408. Its totient is φ = 3542405330406.

The previous prime is 3542405330327. The next prime is 3542405330479. The reversal of 3542405330407 is 7040335042453.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3542405330407 - 211 = 3542405328359 is a prime.

It is a super-3 number, since 3×35424053304073 (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3542405330407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3542405330707) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1771202665203 + 1771202665204.

It is an arithmetic number, because the mean of its divisors is an integer number (1771202665204).

Almost surely, 23542405330407 is an apocalyptic number.

3542405330407 is a deficient number, since it is larger than the sum of its proper divisors (1).

3542405330407 is an equidigital number, since it uses as much as digits as its factorization.

3542405330407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 604800, while the sum is 40.

The spelling of 3542405330407 in words is "three trillion, five hundred forty-two billion, four hundred five million, three hundred thirty thousand, four hundred seven".