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354244044553151 is a prime number
BaseRepresentation
bin101000010001011101101111…
…0011100000111101110111111
31201110021101210112200100210212
41100202323132130013232333
5332412413300401200101
63253225244545223035
7134421200441536304
oct12042733634075677
91643241715610725
10354244044553151
11a2967068033025
1233892a51931a7b
13122880bac1574c
146369708c5d0ab
152ae4a7950b1bb
hex1422ede707bbf

354244044553151 has 2 divisors, whose sum is σ = 354244044553152. Its totient is φ = 354244044553150.

The previous prime is 354244044553111. The next prime is 354244044553169. The reversal of 354244044553151 is 151355440442453.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-354244044553151 is a prime.

It is a super-3 number, since 3×3542440445531513 (a number of 45 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 354244044553151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (354244044553111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177122022276575 + 177122022276576.

It is an arithmetic number, because the mean of its divisors is an integer number (177122022276576).

Almost surely, 2354244044553151 is an apocalyptic number.

354244044553151 is a deficient number, since it is larger than the sum of its proper divisors (1).

354244044553151 is an equidigital number, since it uses as much as digits as its factorization.

354244044553151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520000, while the sum is 50.

The spelling of 354244044553151 in words is "three hundred fifty-four trillion, two hundred forty-four billion, forty-four million, five hundred fifty-three thousand, one hundred fifty-one".