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35427040144019 is a prime number
BaseRepresentation
bin10000000111000100000000…
…01001001010101010010011
311122102210101100011220011122
420003202000021022222103
514120414034234102034
6203202542500032455
710314343036443446
oct1003420011125223
9148383340156148
1035427040144019
1110319583642377
123b81bb809272b
13169c9a8c39664
148a696c1c765d
15416812c5862e
hex20388024aa93

35427040144019 has 2 divisors, whose sum is σ = 35427040144020. Its totient is φ = 35427040144018.

The previous prime is 35427040143893. The next prime is 35427040144063. The reversal of 35427040144019 is 91044104072453.

It is an a-pointer prime, because the next prime (35427040144063) can be obtained adding 35427040144019 to its sum of digits (44).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 35427040144019 - 216 = 35427040078483 is a prime.

It is a super-3 number, since 3×354270401440193 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (35427040147019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17713520072009 + 17713520072010.

It is an arithmetic number, because the mean of its divisors is an integer number (17713520072010).

Almost surely, 235427040144019 is an apocalyptic number.

35427040144019 is a deficient number, since it is larger than the sum of its proper divisors (1).

35427040144019 is an equidigital number, since it uses as much as digits as its factorization.

35427040144019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 483840, while the sum is 44.

The spelling of 35427040144019 in words is "thirty-five trillion, four hundred twenty-seven billion, forty million, one hundred forty-four thousand, nineteen".