354334513004141 has 4 divisors (see below), whose sum is σ = 356456276555232. Its totient is φ = 352212749453052.

The previous prime is 354334513004123. The next prime is 354334513004203. The reversal of 354334513004141 is 141400315433453.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 354334513004141 - 2¹⁰ = 354334513003117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (354334513004741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1060881775295 + ... + 1060881775628.

It is an arithmetic number, because the mean of its divisors is an integer number (89114069138808).

Almost surely, 2^{354334513004141} is an apocalyptic number.

It is an amenable number.

354334513004141 is a deficient number, since it is larger than the sum of its proper divisors (2121763551091).

354334513004141 is a wasteful number, since it uses less digits than its factorization.

354334513004141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2121763551090.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 354334513004141 its reverse (141400315433453), we get a palindrome (495734828437594).

The spelling of 354334513004141 in words is "three hundred fifty-four trillion, three hundred thirty-four billion, five hundred thirteen million, four thousand, one hundred forty-one".