3545125433 has 2 divisors, whose sum is σ = 3545125434. Its totient is φ = 3545125432.

The previous prime is 3545125421. The next prime is 3545125457. The reversal of 3545125433 is 3345215453.

It is a happy number.

3545125433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3402155584 + 142969849 = 58328^2 + 11957^2 .

It is a cyclic number.

It is not a de Polignac number, because 3545125433 - 2⁶ = 3545125369 is a prime.

It is a super-3 number, since 3×3545125433³ (a number of 30 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3545125393 and 3545125402.

It is not a weakly prime, because it can be changed into another prime (3545125403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1772562716 + 1772562717.

It is an arithmetic number, because the mean of its divisors is an integer number (1772562717).

Almost surely, 2^3545125433 is an apocalyptic number.

It is an amenable number.

3545125433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3545125433 is an equidigital number, since it uses as much as digits as its factorization.

3545125433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108000, while the sum is 35.

The square root of 3545125433 is about 59540.9559295112. The cubic root of 3545125433 is about 1524.7917562823.

The spelling of 3545125433 in words is "three billion, five hundred forty-five million, one hundred twenty-five thousand, four hundred thirty-three".