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3545334000641 is a prime number
BaseRepresentation
bin110011100101110110010…
…111111010110000000001
3110112221010102101211111102
4303211312113322300001
5431041321001010031
611312412015424145
7514066452531506
oct63456627726001
913487112354442
103545334000641
111147627686904
12493139225055
131c9428b32814
14c3848c8d4ad
156235028d7cb
hex339765fac01

3545334000641 has 2 divisors, whose sum is σ = 3545334000642. Its totient is φ = 3545334000640.

The previous prime is 3545334000577. The next prime is 3545334000643. The reversal of 3545334000641 is 1460004335453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3199447690000 + 345886310641 = 1788700^2 + 588121^2 .

It is a cyclic number.

It is not a de Polignac number, because 3545334000641 - 26 = 3545334000577 is a prime.

It is a super-2 number, since 2×35453340006412 (a number of 26 digits) contains 22 as substring.

Together with 3545334000643, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3545334000595 and 3545334000604.

It is not a weakly prime, because it can be changed into another prime (3545334000643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1772667000320 + 1772667000321.

It is an arithmetic number, because the mean of its divisors is an integer number (1772667000321).

Almost surely, 23545334000641 is an apocalyptic number.

It is an amenable number.

3545334000641 is a deficient number, since it is larger than the sum of its proper divisors (1).

3545334000641 is an equidigital number, since it uses as much as digits as its factorization.

3545334000641 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 38.

The spelling of 3545334000641 in words is "three trillion, five hundred forty-five billion, three hundred thirty-four million, six hundred forty-one", and thus it is an aban number.