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355002112504993 is a prime number
BaseRepresentation
bin101000010110111110101111…
…0110011110111010010100001
31201112221212111121021100110211
41100231331132303313102201
5333012323311300124433
63255005415152254121
7134530025201032132
oct12055753663672241
91645855447240424
10355002112504993
11a3129606694368
1233995955241341
131231172b7679b5
1463942a01a9c89
152b096463c78cd
hex142df5ecf74a1

355002112504993 has 2 divisors, whose sum is σ = 355002112504994. Its totient is φ = 355002112504992.

The previous prime is 355002112504987. The next prime is 355002112504999. The reversal of 355002112504993 is 399405211200553.

It is a balanced prime because it is at equal distance from previous prime (355002112504987) and next prime (355002112504999).

It can be written as a sum of positive squares in only one way, i.e., 293576286228624 + 61425826276369 = 17134068^2 + 7837463^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-355002112504993 is a prime.

It is not a weakly prime, because it can be changed into another prime (355002112504999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177501056252496 + 177501056252497.

It is an arithmetic number, because the mean of its divisors is an integer number (177501056252497).

Almost surely, 2355002112504993 is an apocalyptic number.

It is an amenable number.

355002112504993 is a deficient number, since it is larger than the sum of its proper divisors (1).

355002112504993 is an equidigital number, since it uses as much as digits as its factorization.

355002112504993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458000, while the sum is 49.

The spelling of 355002112504993 in words is "three hundred fifty-five trillion, two billion, one hundred twelve million, five hundred four thousand, nine hundred ninety-three".