3550102117 has 4 divisors (see below), whose sum is σ = 3575642560. Its totient is φ = 3524561676.

The previous prime is 3550102111. The next prime is 3550102121. The reversal of 3550102117 is 7112010553.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3550102117 - 2³ = 3550102109 is a prime.

It is a super-3 number, since 3×3550102117³ (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3550102091 and 3550102100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3550102111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12770013 + ... + 12770290.

It is an arithmetic number, because the mean of its divisors is an integer number (893910640).

Almost surely, 2^3550102117 is an apocalyptic number.

It is an amenable number.

3550102117 is a deficient number, since it is larger than the sum of its proper divisors (25540443).

3550102117 is a wasteful number, since it uses less digits than its factorization.

3550102117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25540442.

The product of its (nonzero) digits is 1050, while the sum is 25.

The square root of 3550102117 is about 59582.7333797301. The cubic root of 3550102117 is about 1525.5049288486.

The spelling of 3550102117 in words is "three billion, five hundred fifty million, one hundred two thousand, one hundred seventeen".