Base | Representation |
---|---|
bin | 100001000100001101… |
… | …011001111001101111 |
3 | 10101122100020022021122 |
4 | 201010031121321233 |
5 | 1040203022244043 |
6 | 24151012051155 |
7 | 2364552616304 |
oct | 410415317157 |
9 | 111570208248 |
10 | 35504103023 |
11 | 1406a160104 |
12 | 6a6a303abb |
13 | 346a7b44ac |
14 | 1a0b44d0ab |
15 | dcbe59368 |
hex | 844359e6f |
35504103023 has 2 divisors, whose sum is σ = 35504103024. Its totient is φ = 35504103022.
The previous prime is 35504102983. The next prime is 35504103031. The reversal of 35504103023 is 32030140553.
35504103023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (32030140553) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35504103023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 35504102983 and 35504103001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35504103043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17752051511 + 17752051512.
It is an arithmetic number, because the mean of its divisors is an integer number (17752051512).
Almost surely, 235504103023 is an apocalyptic number.
35504103023 is a deficient number, since it is larger than the sum of its proper divisors (1).
35504103023 is an equidigital number, since it uses as much as digits as its factorization.
35504103023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 26.
Adding to 35504103023 its reverse (32030140553), we get a palindrome (67534243576).
The spelling of 35504103023 in words is "thirty-five billion, five hundred four million, one hundred three thousand, twenty-three".
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