Base | Representation |
---|---|
bin | 100001000100010000… |
… | …111011000001110101 |
3 | 10101122101222011012011 |
4 | 201010100323001311 |
5 | 1040203241301031 |
6 | 24151043524221 |
7 | 2364563506555 |
oct | 410420730165 |
9 | 111571864164 |
10 | 35505025141 |
11 | 1406a72a993 |
12 | 6a6a689671 |
13 | 346aa48121 |
14 | 1a0b60d165 |
15 | dcc08c6b1 |
hex | 84443b075 |
35505025141 has 2 divisors, whose sum is σ = 35505025142. Its totient is φ = 35505025140.
The previous prime is 35505025109. The next prime is 35505025207. The reversal of 35505025141 is 14152050553.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34616090916 + 888934225 = 186054^2 + 29815^2 .
It is an emirp because it is prime and its reverse (14152050553) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 35505025141 - 25 = 35505025109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35505025441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17752512570 + 17752512571.
It is an arithmetic number, because the mean of its divisors is an integer number (17752512571).
Almost surely, 235505025141 is an apocalyptic number.
It is an amenable number.
35505025141 is a deficient number, since it is larger than the sum of its proper divisors (1).
35505025141 is an equidigital number, since it uses as much as digits as its factorization.
35505025141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 35505025141 its reverse (14152050553), we get a palindrome (49657075694).
The spelling of 35505025141 in words is "thirty-five billion, five hundred five million, twenty-five thousand, one hundred forty-one".
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