Base | Representation |
---|---|
bin | 10000001001100010101000… |
… | …10100010011010010010001 |
3 | 11122201221012120101202210102 |
4 | 20010301110110103102101 |
5 | 14123312443234230340 |
6 | 203310025325342145 |
7 | 10323446345202101 |
oct | 1004612424232221 |
9 | 148657176352712 |
10 | 35512204211345 |
11 | 10351706526694 |
12 | 3b96605407955 |
13 | 16a7a2bbb5bc4 |
14 | 8aab2ab31201 |
15 | 418b4978b215 |
hex | 204c54513491 |
35512204211345 has 4 divisors (see below), whose sum is σ = 42614645053620. Its totient is φ = 28409763369072.
The previous prime is 35512204211293. The next prime is 35512204211347. The reversal of 35512204211345 is 54311240221553.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 13989814167616 + 21522390043729 = 3740296^2 + 4639223^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35512204211345 is a prime.
It is a super-2 number, since 2×355122042113452 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 35512204211299 and 35512204211308.
It is not an unprimeable number, because it can be changed into a prime (35512204211347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3551220421130 + ... + 3551220421139.
It is an arithmetic number, because the mean of its divisors is an integer number (10653661263405).
Almost surely, 235512204211345 is an apocalyptic number.
It is an amenable number.
35512204211345 is a deficient number, since it is larger than the sum of its proper divisors (7102440842275).
35512204211345 is an equidigital number, since it uses as much as digits as its factorization.
35512204211345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7102440842274.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 35512204211345 its reverse (54311240221553), we get a palindrome (89823444432898).
The spelling of 35512204211345 in words is "thirty-five trillion, five hundred twelve billion, two hundred four million, two hundred eleven thousand, three hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.098 sec. • engine limits •