Base | Representation |
---|---|
bin | 10000001010000011110111… |
… | …00010100010110000011111 |
3 | 11122210122020201120200121211 |
4 | 20011001323202202300133 |
5 | 14124111011241002333 |
6 | 203322135342005251 |
7 | 10324650365026213 |
oct | 1005017342426037 |
9 | 148718221520554 |
10 | 35530042125343 |
11 | 1035922a571477 |
12 | 3b99b63276827 |
13 | 16a96126753bc |
14 | 8ab93dc08943 |
15 | 4193407c8ecd |
hex | 20507b8a2c1f |
35530042125343 has 2 divisors, whose sum is σ = 35530042125344. Its totient is φ = 35530042125342.
The previous prime is 35530042125287. The next prime is 35530042125437. The reversal of 35530042125343 is 34352124003553.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 35530042125343 - 29 = 35530042124831 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 35530042125296 and 35530042125305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35530042125143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17765021062671 + 17765021062672.
It is an arithmetic number, because the mean of its divisors is an integer number (17765021062672).
Almost surely, 235530042125343 is an apocalyptic number.
35530042125343 is a deficient number, since it is larger than the sum of its proper divisors (1).
35530042125343 is an equidigital number, since it uses as much as digits as its factorization.
35530042125343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 40.
Adding to 35530042125343 its reverse (34352124003553), we get a palindrome (69882166128896).
The spelling of 35530042125343 in words is "thirty-five trillion, five hundred thirty billion, forty-two million, one hundred twenty-five thousand, three hundred forty-three".
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