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35530212145 = 57106042429
BaseRepresentation
bin100001000101110001…
…000000001100110001
310101201011100210021011
4201011301000030301
51040231213242040
624153343430521
72365320551221
oct410561001461
9111634323234
1035530212145
111408297329a
126a76bb5441
13347302648c
141a10ac8081
15dce3b53ea
hex845c40331

35530212145 has 4 divisors (see below), whose sum is σ = 42636254580. Its totient is φ = 28424169712.

The previous prime is 35530212139. The next prime is 35530212169. The reversal of 35530212145 is 54121203553.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 24460647201 + 11069564944 = 156399^2 + 105212^2 .

It is a cyclic number.

It is not a de Polignac number, because 35530212145 - 223 = 35521823537 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3553021210 + ... + 3553021219.

It is an arithmetic number, because the mean of its divisors is an integer number (10659063645).

Almost surely, 235530212145 is an apocalyptic number.

It is an amenable number.

35530212145 is a deficient number, since it is larger than the sum of its proper divisors (7106042435).

35530212145 is an equidigital number, since it uses as much as digits as its factorization.

35530212145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7106042434.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 35530212145 its reverse (54121203553), we get a palindrome (89651415698).

The spelling of 35530212145 in words is "thirty-five billion, five hundred thirty million, two hundred twelve thousand, one hundred forty-five".

Divisors: 1 5 7106042429 35530212145