Search a number
-
+
355448678113 is a prime number
BaseRepresentation
bin1010010110000100110…
…01000110011011100001
31020222110211101201121001
411023002121012123201
521310424330144423
6431142454432001
734452230625124
oct5130231063341
91228424351531
10355448678113
1112782156a911
1258a7b062601
1327698683309
14132bd36a3bb
1593a5586cad
hex52c26466e1

355448678113 has 2 divisors, whose sum is σ = 355448678114. Its totient is φ = 355448678112.

The previous prime is 355448678077. The next prime is 355448678129. The reversal of 355448678113 is 311876844553.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 229716028369 + 125732649744 = 479287^2 + 354588^2 .

It is an emirp because it is prime and its reverse (311876844553) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 355448678113 - 213 = 355448669921 is a prime.

It is not a weakly prime, because it can be changed into another prime (355448678213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177724339056 + 177724339057.

It is an arithmetic number, because the mean of its divisors is an integer number (177724339057).

Almost surely, 2355448678113 is an apocalyptic number.

It is an amenable number.

355448678113 is a deficient number, since it is larger than the sum of its proper divisors (1).

355448678113 is an equidigital number, since it uses as much as digits as its factorization.

355448678113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9676800, while the sum is 55.

The spelling of 355448678113 in words is "three hundred fifty-five billion, four hundred forty-eight million, six hundred seventy-eight thousand, one hundred thirteen".