Base | Representation |
---|---|
bin | 110100000010011011110… |
… | …000011000000001111101 |
3 | 110122212100101200220100122 |
4 | 310002123300120001331 |
5 | 432042200120040333 |
6 | 11334445330304325 |
7 | 516234153650525 |
oct | 64023360300175 |
9 | 13585311626318 |
10 | 3576025940093 |
11 | 1159647464222 |
12 | 499083a280a5 |
13 | 1cc2aa674139 |
14 | c511b174685 |
15 | 630499e6798 |
hex | 3409bc1807d |
3576025940093 has 2 divisors, whose sum is σ = 3576025940094. Its totient is φ = 3576025940092.
The previous prime is 3576025939987. The next prime is 3576025940099. The reversal of 3576025940093 is 3900495206753.
3576025940093 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2577781169209 + 998244770884 = 1605547^2 + 999122^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3576025940093 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3576025940099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1788012970046 + 1788012970047.
It is an arithmetic number, because the mean of its divisors is an integer number (1788012970047).
Almost surely, 23576025940093 is an apocalyptic number.
It is an amenable number.
3576025940093 is a deficient number, since it is larger than the sum of its proper divisors (1).
3576025940093 is an equidigital number, since it uses as much as digits as its factorization.
3576025940093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6123600, while the sum is 53.
The spelling of 3576025940093 in words is "three trillion, five hundred seventy-six billion, twenty-five million, nine hundred forty thousand, ninety-three".
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