Base | Representation |
---|---|
bin | 100001101000110011… |
… | …000001101010010101 |
3 | 10110020010021201010222 |
4 | 201220303001222111 |
5 | 1042432143214411 |
6 | 24331540524125 |
7 | 2416015316066 |
oct | 415063015225 |
9 | 113203251128 |
10 | 36117944981 |
11 | 14354702708 |
12 | 6bbb9b0645 |
13 | 3537a185a1 |
14 | 1a68b9a56d |
15 | e15cad4db |
hex | 868cc1a95 |
36117944981 has 4 divisors (see below), whose sum is σ = 36730113600. Its totient is φ = 35505776364.
The previous prime is 36117944977. The next prime is 36117945013. The reversal of 36117944981 is 18944971163.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 36117944981 - 22 = 36117944977 is a prime.
It is a super-4 number, since 4×361179449814 (a number of 43 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (36117944921) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 306084221 + ... + 306084338.
It is an arithmetic number, because the mean of its divisors is an integer number (9182528400).
Almost surely, 236117944981 is an apocalyptic number.
It is an amenable number.
36117944981 is a deficient number, since it is larger than the sum of its proper divisors (612168619).
36117944981 is an equidigital number, since it uses as much as digits as its factorization.
36117944981 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 612168618.
The product of its digits is 1306368, while the sum is 53.
The spelling of 36117944981 in words is "thirty-six billion, one hundred seventeen million, nine hundred forty-four thousand, nine hundred eighty-one".
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