Base | Representation |
---|---|
bin | 1101100011111001… |
… | …1101010000101001 |
3 | 100101200202221012011 |
4 | 3120332131100221 |
5 | 24423401021213 |
6 | 1401115115521 |
7 | 156131424640 |
oct | 33076352051 |
9 | 10350687164 |
10 | 3640251433 |
11 | 15a8910865 |
12 | 857142ba1 |
13 | 460234240 |
14 | 26766a357 |
15 | 1648b303d |
hex | d8f9d429 |
3640251433 has 32 divisors (see below), whose sum is σ = 4609204992. Its totient is φ = 2798496000.
The previous prime is 3640251413. The next prime is 3640251451. The reversal of 3640251433 is 3341520463.
It is a cyclic number.
It is not a de Polignac number, because 3640251433 - 217 = 3640120361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3640251395 and 3640251404.
It is not an unprimeable number, because it can be changed into a prime (3640251413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 456783 + ... + 464683.
It is an arithmetic number, because the mean of its divisors is an integer number (144037656).
Almost surely, 23640251433 is an apocalyptic number.
It is an amenable number.
3640251433 is a deficient number, since it is larger than the sum of its proper divisors (968953559).
3640251433 is a wasteful number, since it uses less digits than its factorization.
3640251433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8065.
The product of its (nonzero) digits is 25920, while the sum is 31.
The square root of 3640251433 is about 60334.4962107085. The cubic root of 3640251433 is about 1538.3097541473.
Adding to 3640251433 its reverse (3341520463), we get a palindrome (6981771896).
The spelling of 3640251433 in words is "three billion, six hundred forty million, two hundred fifty-one thousand, four hundred thirty-three".
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