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36527415091331 is a prime number
BaseRepresentation
bin10000100111000101100111…
…00110011110000010000011
311210022222122100202221220212
420103202303212132002003
514241431121230410311
6205404243550024335
710460006253251033
oct1023426346360203
9153288570687825
1036527415091331
111070320a60787a
12411b3114a80ab
13174c69c5c4038
14903d173b38c3
154352665bec8b
hex2138b399e083

36527415091331 has 2 divisors, whose sum is σ = 36527415091332. Its totient is φ = 36527415091330.

The previous prime is 36527415091087. The next prime is 36527415091333. The reversal of 36527415091331 is 13319051472563.

It is a strong prime.

It is an emirp because it is prime and its reverse (13319051472563) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 36527415091331 - 230 = 36526341349507 is a prime.

It is a super-2 number, since 2×365274150913312 (a number of 28 digits) contains 22 as substring.

Together with 36527415091333, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 36527415091331.

It is not a weakly prime, because it can be changed into another prime (36527415091333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 18263707545665 + 18263707545666.

It is an arithmetic number, because the mean of its divisors is an integer number (18263707545666).

Almost surely, 236527415091331 is an apocalyptic number.

36527415091331 is a deficient number, since it is larger than the sum of its proper divisors (1).

36527415091331 is an equidigital number, since it uses as much as digits as its factorization.

36527415091331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2041200, while the sum is 50.

The spelling of 36527415091331 in words is "thirty-six trillion, five hundred twenty-seven billion, four hundred fifteen million, ninety-one thousand, three hundred thirty-one".