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36551427537433 is a prime number
BaseRepresentation
bin10000100111110010010101…
…10110101011101000011001
311210102021121211102121110111
420103321022312223220121
514242324310422144213
6205423254412044321
710461516306546364
oct1023711266535031
9153367554377414
1036551427537433
1110712411a50a56
124123ab31636a1
131751a2835a423
1490515452d0db
15435bbe71da3d
hex213e4adaba19

36551427537433 has 2 divisors, whose sum is σ = 36551427537434. Its totient is φ = 36551427537432.

The previous prime is 36551427537409. The next prime is 36551427537589. The reversal of 36551427537433 is 33473572415563.

36551427537433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36215686094809 + 335741442624 = 6017947^2 + 579432^2 .

It is a cyclic number.

It is not a de Polignac number, because 36551427537433 - 213 = 36551427529241 is a prime.

It is not a weakly prime, because it can be changed into another prime (36551427537733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 18275713768716 + 18275713768717.

It is an arithmetic number, because the mean of its divisors is an integer number (18275713768717).

Almost surely, 236551427537433 is an apocalyptic number.

It is an amenable number.

36551427537433 is a deficient number, since it is larger than the sum of its proper divisors (1).

36551427537433 is an equidigital number, since it uses as much as digits as its factorization.

36551427537433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 95256000, while the sum is 58.

The spelling of 36551427537433 in words is "thirty-six trillion, five hundred fifty-one billion, four hundred twenty-seven million, five hundred thirty-seven thousand, four hundred thirty-three".