Base | Representation |
---|---|
bin | 110101001101111110100… |
… | …110101100001010110001 |
3 | 110221121201110110002212222 |
4 | 311031332212230022301 |
5 | 434404311124143442 |
6 | 11440022324530425 |
7 | 525135240432023 |
oct | 65157646541261 |
9 | 13847643402788 |
10 | 3657141240497 |
11 | 118aa91985a78 |
12 | 4b0941250a15 |
13 | 206b36885c04 |
14 | c90140b2013 |
15 | 651e5d6e8d2 |
hex | 3537e9ac2b1 |
3657141240497 has 2 divisors, whose sum is σ = 3657141240498. Its totient is φ = 3657141240496.
The previous prime is 3657141240469. The next prime is 3657141240509. The reversal of 3657141240497 is 7940421417563.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3111329098816 + 545812141681 = 1763896^2 + 738791^2 .
It is a cyclic number.
It is not a de Polignac number, because 3657141240497 - 212 = 3657141236401 is a prime.
It is not a weakly prime, because it can be changed into another prime (3657141240097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1828570620248 + 1828570620249.
It is an arithmetic number, because the mean of its divisors is an integer number (1828570620249).
Almost surely, 23657141240497 is an apocalyptic number.
It is an amenable number.
3657141240497 is a deficient number, since it is larger than the sum of its proper divisors (1).
3657141240497 is an equidigital number, since it uses as much as digits as its factorization.
3657141240497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5080320, while the sum is 53.
The spelling of 3657141240497 in words is "three trillion, six hundred fifty-seven billion, one hundred forty-one million, two hundred forty thousand, four hundred ninety-seven".
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