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38008104131 is a prime number
BaseRepresentation
bin100011011001011101…
…011010010011000011
310122002211221202001102
4203121131122103003
51110320033313011
625243301325015
72513606361134
oct433135322303
9118084852042
1038008104131
1115134647208
127448a0676b
1337794b4b5a
141ba7c21c8b
15ec6bc573b
hex8d975a4c3

38008104131 has 2 divisors, whose sum is σ = 38008104132. Its totient is φ = 38008104130.

The previous prime is 38008104073. The next prime is 38008104133. The reversal of 38008104131 is 13140180083.

38008104131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-38008104131 is a prime.

It is a super-2 number, since 2×380081041312 (a number of 22 digits) contains 22 as substring.

Together with 38008104133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 38008104094 and 38008104103.

It is not a weakly prime, because it can be changed into another prime (38008104133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19004052065 + 19004052066.

It is an arithmetic number, because the mean of its divisors is an integer number (19004052066).

Almost surely, 238008104131 is an apocalyptic number.

38008104131 is a deficient number, since it is larger than the sum of its proper divisors (1).

38008104131 is an equidigital number, since it uses as much as digits as its factorization.

38008104131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 29.

The spelling of 38008104131 in words is "thirty-eight billion, eight million, one hundred four thousand, one hundred thirty-one".