3806833138253 has 4 divisors (see below), whose sum is σ = 3806837788668. Its totient is φ = 3806828487840.

The previous prime is 3806833138249. The next prime is 3806833138261. The reversal of 3806833138253 is 3528313386083.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 1598108090569 + 2208725047684 = 1264163^2 + 1486178^2 .

It is a cyclic number.

It is not a de Polignac number, because 3806833138253 - 2² = 3806833138249 is a prime.

It is a super-3 number, since 3×3806833138253³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3806833138195 and 3806833138204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3806833134253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 734618 + ... + 2855403.

It is an arithmetic number, because the mean of its divisors is an integer number (951709447167).

Almost surely, 2^{3806833138253} is an apocalyptic number.

It is an amenable number.

3806833138253 is a deficient number, since it is larger than the sum of its proper divisors (4650415).

3806833138253 is a wasteful number, since it uses less digits than its factorization.

3806833138253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4650414.

The product of its (nonzero) digits is 7464960, while the sum is 53.

The spelling of 3806833138253 in words is "three trillion, eight hundred six billion, eight hundred thirty-three million, one hundred thirty-eight thousand, two hundred fifty-three".