Base | Representation |
---|---|
bin | 1011001001111001010… |
… | …11100001010110101101 |
3 | 1100122021202100222022101 |
4 | 11210330223201112231 |
5 | 22234414123143432 |
6 | 452023305015101 |
7 | 36455535235036 |
oct | 5447453412655 |
9 | 1318252328271 |
10 | 383270131117 |
11 | 1385a8aa7285 |
12 | 62344484491 |
13 | 2a1b05b8643 |
14 | 1479c31da8d |
15 | 9e82cd04e7 |
hex | 593cae15ad |
383270131117 has 2 divisors, whose sum is σ = 383270131118. Its totient is φ = 383270131116.
The previous prime is 383270131061. The next prime is 383270131121. The reversal of 383270131117 is 711131072383.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 209256842916 + 174013288201 = 457446^2 + 417149^2 .
It is an emirp because it is prime and its reverse (711131072383) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-383270131117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (383270131157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 191635065558 + 191635065559.
It is an arithmetic number, because the mean of its divisors is an integer number (191635065559).
Almost surely, 2383270131117 is an apocalyptic number.
It is an amenable number.
383270131117 is a deficient number, since it is larger than the sum of its proper divisors (1).
383270131117 is an equidigital number, since it uses as much as digits as its factorization.
383270131117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21168, while the sum is 37.
The spelling of 383270131117 in words is "three hundred eighty-three billion, two hundred seventy million, one hundred thirty-one thousand, one hundred seventeen".
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