38365148011343 has 4 divisors (see below), whose sum is σ = 38381879434488. Its totient is φ = 38348416588200.

The previous prime is 38365148011313. The next prime is 38365148011387. The reversal of 38365148011343 is 34311084156383.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-38365148011343 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 38365148011291 and 38365148011300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (38365148011313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8365708133 + ... + 8365712718.

It is an arithmetic number, because the mean of its divisors is an integer number (9595469858622).

Almost surely, 2^{38365148011343} is an apocalyptic number.

38365148011343 is a deficient number, since it is larger than the sum of its proper divisors (16731423145).

38365148011343 is a wasteful number, since it uses less digits than its factorization.

38365148011343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16731423144.

The product of its (nonzero) digits is 2488320, while the sum is 50.

The spelling of 38365148011343 in words is "thirty-eight trillion, three hundred sixty-five billion, one hundred forty-eight million, eleven thousand, three hundred forty-three".