Search a number
-
+
3840248680117 is a prime number
BaseRepresentation
bin110111111000100000101…
…010001000111010110101
3111121010100112101210220221
4313320200222020322311
51000404312130230432
612100104052454341
7544306641123613
oct67704052107265
914533315353827
103840248680117
1112507052a0573
1252032361a3b1
1321b19822b815
14d3c248806b3
1569d61290b97
hex37e20a88eb5

3840248680117 has 2 divisors, whose sum is σ = 3840248680118. Its totient is φ = 3840248680116.

The previous prime is 3840248680069. The next prime is 3840248680123. The reversal of 3840248680117 is 7110868420483.

3840248680117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2204034190801 + 1636214489316 = 1484599^2 + 1279146^2 .

It is a cyclic number.

It is not a de Polignac number, because 3840248680117 - 211 = 3840248678069 is a prime.

It is a super-2 number, since 2×38402486801172 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3840248680127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1920124340058 + 1920124340059.

It is an arithmetic number, because the mean of its divisors is an integer number (1920124340059).

Almost surely, 23840248680117 is an apocalyptic number.

It is an amenable number.

3840248680117 is a deficient number, since it is larger than the sum of its proper divisors (1).

3840248680117 is an equidigital number, since it uses as much as digits as its factorization.

3840248680117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2064384, while the sum is 52.

The spelling of 3840248680117 in words is "three trillion, eight hundred forty billion, two hundred forty-eight million, six hundred eighty thousand, one hundred seventeen".