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38407135536293 is a prime number
BaseRepresentation
bin10001011101110010110111…
…01010111010010010100101
312000222200112022102022222012
420232321123222322102211
520013230303144130133
6213403554450444005
711042552423355326
oct1056713352722245
9160880468368865
1038407135536293
1111268413813717
124383687b93605
131857a14a81064
1496acb574a44d
154690cecc5b48
hex22ee5baba4a5

38407135536293 has 2 divisors, whose sum is σ = 38407135536294. Its totient is φ = 38407135536292.

The previous prime is 38407135536257. The next prime is 38407135536307. The reversal of 38407135536293 is 39263553170483.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37459271678404 + 947863857889 = 6120398^2 + 973583^2 .

It is a cyclic number.

It is not a de Polignac number, because 38407135536293 - 28 = 38407135536037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (38407135530293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19203567768146 + 19203567768147.

It is an arithmetic number, because the mean of its divisors is an integer number (19203567768147).

It is a 1-persistent number, because it is pandigital, but 2⋅38407135536293 = 76814271072586 is not.

Almost surely, 238407135536293 is an apocalyptic number.

It is an amenable number.

38407135536293 is a deficient number, since it is larger than the sum of its proper divisors (1).

38407135536293 is an equidigital number, since it uses as much as digits as its factorization.

38407135536293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48988800, while the sum is 59.

The spelling of 38407135536293 in words is "thirty-eight trillion, four hundred seven billion, one hundred thirty-five million, five hundred thirty-six thousand, two hundred ninety-three".