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384172855413 = 3128057618471
BaseRepresentation
bin1011001011100100111…
…11001001000001110101
31100201121200000010020120
411211302133021001311
522243241222333123
6452253033322153
736520106251224
oct5456237110165
91321550003216
10384172855413
11138a2161a416
1262556866359
132a2c5627029
1414846188cbb
159ed71992e3
hex59727c9075

384172855413 has 4 divisors (see below), whose sum is σ = 512230473888. Its totient is φ = 256115236940.

The previous prime is 384172855399. The next prime is 384172855433. The reversal of 384172855413 is 314558271483.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 384172855413 - 216 = 384172789877 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (384172855433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64028809233 + ... + 64028809238.

It is an arithmetic number, because the mean of its divisors is an integer number (128057618472).

Almost surely, 2384172855413 is an apocalyptic number.

It is an amenable number.

384172855413 is a deficient number, since it is larger than the sum of its proper divisors (128057618475).

384172855413 is a wasteful number, since it uses less digits than its factorization.

384172855413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 128057618474.

The product of its digits is 3225600, while the sum is 51.

The spelling of 384172855413 in words is "three hundred eighty-four billion, one hundred seventy-two million, eight hundred fifty-five thousand, four hundred thirteen".

Divisors: 1 3 128057618471 384172855413