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384233144137 is a prime number
BaseRepresentation
bin1011001011101100001…
…01000111111101001001
31100201202212110002211021
411211312011013331021
522243402141103022
6452303025432441
736521440560133
oct5456605077511
91321685402737
10384233144137
11138a52658207
1262572a9b721
132a304c7552b
14148501a0053
159edc6077c7
hex5976147f49

384233144137 has 2 divisors, whose sum is σ = 384233144138. Its totient is φ = 384233144136.

The previous prime is 384233144131. The next prime is 384233144147. The reversal of 384233144137 is 731441332483.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 358691990281 + 25541153856 = 598909^2 + 159816^2 .

It is a cyclic number.

It is not a de Polignac number, because 384233144137 - 23 = 384233144129 is a prime.

It is a super-3 number, since 3×3842331441373 (a number of 36 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 384233144093 and 384233144102.

It is not a weakly prime, because it can be changed into another prime (384233144131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 192116572068 + 192116572069.

It is an arithmetic number, because the mean of its divisors is an integer number (192116572069).

Almost surely, 2384233144137 is an apocalyptic number.

It is an amenable number.

384233144137 is a deficient number, since it is larger than the sum of its proper divisors (1).

384233144137 is an equidigital number, since it uses as much as digits as its factorization.

384233144137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 580608, while the sum is 43.

The spelling of 384233144137 in words is "three hundred eighty-four billion, two hundred thirty-three million, one hundred forty-four thousand, one hundred thirty-seven".