Base | Representation |
---|---|
bin | 10001011110100011001001… |
… | …11101101010100100011111 |
3 | 12001002011110010020010010022 |
4 | 20233101210331222210133 |
5 | 20014141402140020414 |
6 | 213423523220502355 |
7 | 11044461041326415 |
oct | 1057214475524437 |
9 | 161064403203108 |
10 | 38433061251359 |
11 | 11278408146115 |
12 | 438870254a9bb |
13 | 185a2b7015768 |
14 | 96c254a252b5 |
15 | 469aeada418e |
hex | 22f464f6a91f |
38433061251359 has 2 divisors, whose sum is σ = 38433061251360. Its totient is φ = 38433061251358.
The previous prime is 38433061251287. The next prime is 38433061251397. The reversal of 38433061251359 is 95315216033483.
It is a strong prime.
It is an emirp because it is prime and its reverse (95315216033483) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 38433061251359 - 216 = 38433061185823 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 38433061251359.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (38433061251859) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19216530625679 + 19216530625680.
It is an arithmetic number, because the mean of its divisors is an integer number (19216530625680).
Almost surely, 238433061251359 is an apocalyptic number.
38433061251359 is a deficient number, since it is larger than the sum of its proper divisors (1).
38433061251359 is an equidigital number, since it uses as much as digits as its factorization.
38433061251359 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6998400, while the sum is 53.
The spelling of 38433061251359 in words is "thirty-eight trillion, four hundred thirty-three billion, sixty-one million, two hundred fifty-one thousand, three hundred fifty-nine".
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