Base | Representation |
---|---|
bin | 10001100000000000110110… |
… | …10101101100101110011101 |
3 | 12001020222021220211002121121 |
4 | 20300000123111230232131 |
5 | 20021002413101121323 |
6 | 213503003014330541 |
7 | 11051221450531666 |
oct | 1060003325545635 |
9 | 161228256732547 |
10 | 38483365645213 |
11 | 11297781713835 |
12 | 4396401359a51 |
13 | 1861c72b61198 |
14 | 97086795036d |
15 | 46b092324a5d |
hex | 23001b56cb9d |
38483365645213 has 2 divisors, whose sum is σ = 38483365645214. Its totient is φ = 38483365645212.
The previous prime is 38483365645189. The next prime is 38483365645301. The reversal of 38483365645213 is 31254656338483.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28134675549369 + 10348690095844 = 5304213^2 + 3216938^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-38483365645213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (38483365645013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19241682822606 + 19241682822607.
It is an arithmetic number, because the mean of its divisors is an integer number (19241682822607).
Almost surely, 238483365645213 is an apocalyptic number.
It is an amenable number.
38483365645213 is a deficient number, since it is larger than the sum of its proper divisors (1).
38483365645213 is an equidigital number, since it uses as much as digits as its factorization.
38483365645213 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 149299200, while the sum is 61.
The spelling of 38483365645213 in words is "thirty-eight trillion, four hundred eighty-three billion, three hundred sixty-five million, six hundred forty-five thousand, two hundred thirteen".
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