38680751041253 has 4 divisors (see below), whose sum is σ = 38680767853728. Its totient is φ = 38680734228780.

The previous prime is 38680751041241. The next prime is 38680751041279. The reversal of 38680751041253 is 35214015708683.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 38680751041253 - 2¹⁸ = 38680750779109 is a prime.

It is a super-2 number, since 2×38680751041253² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 38680751041195 and 38680751041204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (38680751041213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4280051 + ... + 9781632.

It is an arithmetic number, because the mean of its divisors is an integer number (9670191963432).

Almost surely, 2^{38680751041253} is an apocalyptic number.

It is an amenable number.

38680751041253 is a deficient number, since it is larger than the sum of its proper divisors (16812475).

38680751041253 is a wasteful number, since it uses less digits than its factorization.

38680751041253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16812474.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 38680751041253 in words is "thirty-eight trillion, six hundred eighty billion, seven hundred fifty-one million, forty-one thousand, two hundred fifty-three".